Question

Find the equivalent resistance of this circuit with respect to terminals a and b?

Answer 1

To calculate the equivalent resistance of a circuit, analyze the arrangement of resistors, sum resistances in series, and use the parallel resistance formula for parallel arrangements, simplifying until the entire circuit is reduced to a single equivalent resistance.

Step-by-step explanation:

To find the equivalent resistance of a circuit with respect to terminals a and b, one must consider the arrangement of resistors. If resistors are in series, their resistances simply add up. For resistors in parallel, the equivalent resistance can be found using the formula:

• 1/Requiv = 1/R1 + 1/R2 + ... + 1/Rn.

Without a specific diagram or resistor values, we can't calculate an exact value, but the procedure involves analyzing the circuit, combining resistances in series and parallel, and simplifying step by step until one equivalent resistance is found for the entire circuit.

Answer 2

In this case, the equivalent resistance of the circuit between terminals a and b is approximately 122.97 ohms.

Step-by-step explanation:

To find the equivalent resistance of the circuit between terminals a and b, we need to follow the given instructions.

1. Neglect the 60-ohm resistor: Since it is left open, we can ignore it for the calculation of the equivalent resistance.

2. Identify series and parallel resistors:

1. - The 15, 100, and 150 ohm resistors are in series with each other.
2. - The result of the series resistors is in parallel with the left 100-ohm resistor.
3. - The combination of the parallel resistors and the left 100-ohm resistor is in series with the 50-ohm resistor.

3. Calculate the equivalent resistance:

- The equivalent resistance of the series resistors (15, 100, and 150 ohms) is their sum:

R-series = 15 + 100 + 150 = 265 ohms

- The equivalent resistance of the parallel combination (R-series and the left 100-ohm resistor) is given by:

1/R-parallel = 1/R-series + 1/100

Solving for R_parallel:

R-parallel = 1 / (1/R-series + 1/100)

= 1 / (1/265 + 1/100)

≈ 72.97 ohms

- The equivalent resistance of the whole circuit (R-parallel and the 50-ohm resistor in series) is their sum:

R-eq = R-parallel + 50

≈ 72.97 + 50

≈ 122.97 ohms

Therefore, the equivalent resistance of the circuit between terminals a and b is approximately 122.97 ohms.

Your question is incomplete, but most probably the full question was:

Find the equivalent resistance of this circuit with respect to terminals a and b?

Hint: ( the 15, (right) 100, and 150 ohm-resistors are all in series, and the result is in parallel with the left 100-ohm resistor, and whole thing comes in series with the 50-ohm resistor)