Question

Let , −6 5 be a point on the terminal side of θ. Find the exact values of sinθ, secθ, and tanθ. Sinθ = secθ = tanθ

Answer 1

Explanation:

From the information given:

`r^2 = x^2 +y^2`

`r^2 = (-6)^2 + (5)^2`

`r^2 = 36 +25`

`r^2 =61`

`r = √(61)`

`Sin \theta = (y)/(r) = (5)/(√(61))`

`Cos \theta = (x)/(r) = (- 6 )/(√(61))`

`Sec \theta = (1)/(cos \theta) = (√(61))/(5)`

`tan \theta = (Sin \theta )/(Cos \theta)`

`tan \theta = \frac{(5)/(√(61)) }{\frac{{-6} }{√(61)} }`

`tan \theta = {(5)/(√(61)) }* (√(61) )/(-6)`

`tan \theta = {(5)/(-6) }`