Question

The pressure of a gas sample at 30.0 °C is increased from 1.10 atm to 2.30 atm by heating at a constant volume. What is the temperature (in °C) of the gas at 2.30 atm?

Answer 1

To find the temperature of the gas at a pressure of 2.30 atm, we can use the combined gas law and rearrange it to solve for temperature.

Step-by-step explanation:

To find the temperature of the gas at 2.30 atm, we can use the combined gas law: PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Since the volume is constant in this case, we can rearrange the formula to solve for the temperature:

T₂ = T₁ * (P₂/P₁)

Using the given values, T₁ = 30.0 °C + 273.15 = 303.15 K, P₁ = 1.10 atm, and P₂ = 2.30 atm:

T₂ = 303.15 K * (2.30/1.10) = 635.11 K