157k views
3 votes
Which of the halides shown cannot be used for a Friedel-Crafts alkylation reaction?

1) CH₃CH₂CH₂Cl
2) CH₃CH₂CH₂Br
3) CH₃CH₂CH₂I
4) CH₃CH₂CH₂F

User Valachio
by
8.5k points

1 Answer

5 votes

Final answer:

The halide that cannot be used for a Friedel-Crafts alkylation reaction is CH3CH2CH2F due to the strong carbon-fluorine bond which is difficult to break during the reaction.

Step-by-step explanation:

The halide that cannot be used for a Friedel-Crafts alkylation reaction among the options provided is CH3CH2CH2F (4). This is because fluorine, being the smallest and most electronegative of the halogens, forms the strongest carbon-halogen bond, which is difficult to break during the alkylation process. Alkyl fluorides are also less reactive due to their high strength carbon-fluorine bond and do not usually participate in Friedel-Crafts reactions. On the other hand, the alkyl chlorides, bromides, and iodides (1, 2, and 3 respectively) can be used in Friedel-Crafts alkylation as their carbon-halogen bonds are more reactive and can be cleaved under the conditions of the reaction.

User SUPARNA SOMAN
by
8.5k points