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A 2000 kg car traveling at a speed of 14 m/s skids to a halt on wet concrete where μk = 0.40. What is the stopping distance of the car?

User Manvir
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Final answer:

The stopping distance of the car on wet concrete is 5.97 meters.

Step-by-step explanation:

To find the stopping distance of the car, we can use the formula d = v^2 / (2a), where d is the distance, v is the initial velocity, and a is the acceleration.

Given that the car is skidding to a halt on wet concrete, we can use the coefficient of kinetic friction (μk) to calculate the acceleration.

The formula is μk = a/g, where g is the acceleration due to gravity. Rearranging the formula, we have a = μk * g.

Plugging in the values, we have a = 0.40 * 9.8 m/s^2 = 3.92 m/s^2.

Substituting the values into the initial formula, we have d = (14 m/s)^2 / (2 * 3.92 m/s^2) = 5.97 m.

Therefore, the stopping distance of the car is 5.97 meters on wet concrete.

User Pablo CG
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