Question

How much charge does a battery have to supply to a 6.00 μF capacitor to create a potential difference of 1.50 V across its plates?

Answer 1

The battery must supply a charge of 9.00 µC to a 6.00 µF capacitor to create a potential difference of 1.50 V across its plates.

Step-by-step explanation:

To find out how much charge a battery has to supply to a 6.00 µF capacitor to create a potential difference of 1.50 V across its plates, we use the formula relating charge (Q), capacitance (C), and potential difference (ΔV), which is Q = C ΔV. In this case, the capacitance C is 6.00 µF (or 6.00 x 10^-6 F) and the potential difference ΔV is 1.50 V.

Substituting the given values into the formula, we get:

Q = (6.00 x 10^-6 F)(1.50 V) = 9.00 x 10^-6 C

So, the battery must supply a charge of 9.00 µC to the capacitor.