Final answer:
To determine the exact volume of boiling water needed to dissolve 25 g of phthalic acid, we would need information about the solubility of phthalic acid in water. However, we can make general assumptions and calculate an approximate volume based on the assumptions.
Step-by-step explanation:
To determine how many milliliters of boiling water are required to dissolve 25 g of phthalic acid, we need to know the solubility of phthalic acid in water. The solubility of phthalic acid at a given temperature can be represented by its solubility curve. Without that information, it is difficult to determine the exact volume of boiling water needed.
However, we can make some general assumptions. Let's assume that phthalic acid is completely soluble in water. In that case, we can use the concept of solubility to calculate the approximate volume of boiling water needed.
The molar mass of phthalic acid (C8H6O4) is 166.14 g/mol. To convert 25 g of phthalic acid to moles, we divide the mass by the molar mass:
25 g ÷ 166.14 g/mol = 0.1507 mol
If phthalic acid completely dissociates in water, we can assume a 1:1 ratio between the number of moles of phthalic acid and the number of moles of water molecules required to dissolve it. Therefore, we need approximately 0.1507 mol of water molecules.
The molar volume of an ideal gas at 1 atm and 25°C is approximately 24.79 L/mol. Therefore, the volume of water needed can be calculated as:
0.1507 mol × 24.79 L/mol = 3.73 L
So, approximately 3.73 liters of boiling water would be required to dissolve 25 g of phthalic acid under the assumption of complete solubility in water.