Final answer:
The predicted hybridization at an atom surrounded by two double bonds is sp hybridization for the atoms involved in the double bonds, and sp³ hybridization for the other atoms.
Step-by-step explanation:
Carbon atoms 1 and 4 have four single bonds and are thus tetrahedral with sp³ hybridization. Carbon atoms 2 and 3 are involved in the triple bond, so they have linear geometries and would be classified as sp hybrids.