Final answer:
The integral of 13sec(x)tan(x)dx is 13sec(x) + C, where C is the constant of integration. This follows from the fact that the derivative of sec(x) is sec(x)tan(x) and integration reverses differentiation.
Step-by-step explanation:
To find the indefinite integral of 13sec(x)tan(x)dx, we can recognize that the derivative of sec(x) is sec(x)tan(x). Thus, integrating sec(x)tan(x) will give us sec(x). Since we have a constant multiple of 13, the integral becomes:
∫ 13sec(x)tan(x)dx = 13 ∫ sec(x)tan(x)dx
This simplifies to:
13sec(x) + C
where C is the constant of integration. To confirm our result, a computer algebra system can be used.