Final answer:
To find the number of chlorine atoms in 9.3 g of CCl4, we calculate the number of moles of CCl4 and then use Avogadro's number to convert the moles of chlorine to atoms. The answer is approximately 1.456 x 10^23 chlorine atoms.
Step-by-step explanation:
To calculate the number of chlorine atoms in 9.3 g of CCl4 (carbon tetrachloride), we can start by determining the molar mass of CCl4. The molar mass of CCl4 is 12.01 g/mol for carbon and 35.45 g/mol for each chlorine (using the average atomic mass of chlorine, which accounts for its isotopes). As there are four chlorine atoms in each CCl4 molecule, the total molar mass is 12.01 + (4 x 35.45) = 153.81 g/mol.
Next, we can use this to find out how many moles of CCl4 we have in 9.3 g:
Moles of CCl4 = Mass of CCl4 / Molar mass of CCl4
= 9.3 g / 153.81 g/mol
= 0.0605 mol
Now, since each mole of CCl4 contains 4 moles of chlorine atoms, we can calculate the number of moles of chlorine atoms in the sample:
Moles of Cl atoms = 0.0605 mol CCl4 x 4 mol Cl / 1 mol CCl4
= 0.242 mol Cl
Lastly, to find the actual number of atoms, we use Avogadro's number, which is 6.022 x 1023 atoms/mol.
Number of Cl atoms = 0.242 mol Cl x 6.022 x 1023 atoms/mol
= 1.456 x 1023 atoms of Cl