Question

A 50.0 g object absorbs 500 J of heat and increases in temperature by 40.0 oC. What is the specific heat capacity of the object?

Answer 1

250 J kg^-1K^-1

Step-by-step explanation:

use the formula

`S = (Q)/(m(T_(1)-T_(2)) )`

here S = Specific heat capacity

Q = heat energy = 500J

m = mass in kg = 50X10^-3 kg

T1 - T2 = Temperature difference = 40