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A ball is kicked with an initial velocity of 17.0 m/s in the horizontal direction and 11.0 m/s in the vertical direction. (Assume the ball is kicked from the ground.)

(a) At what speed (in m/s) does the ball hit the ground? m/s
(b) For how long (in s) does the ball remain in the air? S
(c) What maximum height (in m) is attained by the ball? m

User Meryan
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1 Answer

6 votes

Final answer:

The speed the ball hits the ground is found by combining the final horizontal and vertical velocities, with the time in the air and maximum height determined by the initial vertical velocity and gravitational acceleration.

Step-by-step explanation:

To solve projectile motion questions like the one you've posted, we will apply the principles of physics to find the speed the ball hits the ground, the time it remains in the air, and the maximum height it reaches. Since there is no air resistance, we'll use kinematic equations that describe projectile motion.

  • a) Speed upon hitting the ground: The initial velocities in the horizontal (17.0 m/s) and vertical (11.0 m/s) directions remain consistent in their respective axes, with only the vertical direction affected by gravity. The velocity upon hitting the ground can be calculated using the Pythagorean theorem with the final horizontal velocity (which stays 17.0 m/s) and the final vertical velocity, which can be found using kinematic equations.
  • b) Time in the air: The time a projectile is in the air is determined by the vertical component. Using the initial vertical velocity and acceleration due to gravity, the time to reach the peak can be calculated, and doubling this time gives the total time in the air.
  • c) Maximum height: The maximum height is attained at the peak of the projectile's path. By applying kinematic equations using the initial vertical velocity and gravity, the maximum height can be found.

User ALittleDiff
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