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Assume that e = 47.5 V. The battery has negligible internal resistance. What is the question?

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Final answer:

The student's question involves calculating different electrical quantities associated with a circuit that includes a battery with an emf of 47.5 V, accounting for the internal resistance, which is considered negligible. The formula Vterminal = e - Ir aids in deriving these quantities, and if internal resistance was significant, it could be found along with the emf from a voltage-current graph.

Step-by-step explanation:

The student appears to be asking about the concept of electromotive force (emf) and internal resistance in a circuit in the context of Physics. When given the emf (e) of a battery as 47.5 V and considering negligible internal resistance, the question likely relates to finding quantities like current through a resistor, potential difference across the terminals, or power dissipated in the circuit comprising the battery and external components. The formula for terminal voltage, Vterminal = e - Ir (where I is the current and r is the internal resistanc), is crucial here, particularly if there are specific values for current or resistors given in a circuit diagram that's referenced.

In scenarios where internal resistance is not negligible, the emf and internal resistance can be determined by plotting measured currents and voltages and analyzing the resulting graph. For example, if a voltage-current graph for a battery shows a linear relationship represented by V = -0.50I + 6.0, this suggests an internal resistance of 0.5 ohms and an emf of 6 V.

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