Two randomly selected individuals in a specific population: probability of both having O blood type is 0.1764, and matching phenotypes is 0.4621.
Probabilities of Blood Phenotypes:
Probability of both phenotypes being O:
P(O) = 0.42 (probability of one individual having O blood type)
Since the phenotypes are independent, the probability of both being O is:
P(O) * P(O) = 0.42 * 0.42 = 0.1764 (rounded to four decimal places)
Probability of phenotypes matching:
We need to consider all cases where the phenotypes match:
AA: P(A) * P(A) = 0.49 * 0.49 = 0.2401
BB: P(B) * P(B) = 0.08 * 0.08 = 0.0064
AB: P(A) * P(B) = 0.49 * 0.08 = 0.0392
OO: P(O) * P(O) = 0.42 * 0.42 = 0.1764
Total probability of matching phenotypes:
0.2401 (AA) + 0.0064 (BB) + 0.0392 (AB) + 0.1764 (OO) = 0.4621 (rounded to four decimal places)
Therefore:
Probability of both phenotypes being O: 0.1764
Probability of phenotypes matching: 0.4621
Q- Suppose that the proportions of blood phenotypes in a particular population are as follows:
A - 0.49
B - 0.08
AB - 0.01
O - 0.42
Assuming that the phenotypes of two randomly selected individuals are independent of one another, what is the probability that both phenotypes are O? (Enter your answer to four decimal places.)______
What is the probability that the phenotypes of two randomly selected individuals match? (Enter your answer to four decimal places.)______