Question

How much charge is stored in the 10.0 μF capacitor?

Answer 1

To calculate the amount of stored charge in a 10.0 µF capacitor charged to 9.00 × 10³ V, use the formula Q = CV. The result is 90 µC of charge stored in the capacitor.

Step-by-step explanation:

To find the amount of stored charge in a 10.0 µF capacitor, you can use the relationship Q = CV, where Q is the charge in coulombs, C is the capacitance in farads, and V is the voltage in volts. Given that the capacitor in question is part of a heart defibrillator and is charged to a voltage of 9.00 × 10³ V, you can calculate the charge stored using the following steps:

1. First, convert the capacitance from microfarads to farads: 10.0 µF = 10.0 × 10⁻⁶ F.
2. Next, use the formula Q = CV to calculate the charge: Q = (10.0 × 10⁻⁶ F)(9.00 × 10³ V).
3. Multiply these values to get the charge: Q = 9.00 × 10⁻² C.
4. The stored charge is therefore 9.00 × 10⁻² C or 90 µC.

Using this method, you can find that the capacitor stores a charge of 90 µC when charged to a voltage of 9.00 × 10³ V.