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Solve the following initial value problem (IVP) explicitly: (2x⁶) dx/dt = -t sin(t²), x(0) = -4

User Czheo
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Final answer:

To solve the given initial value problem (IVP), we can separate the variables and integrate both sides. The explicit solution to the IVP is x(t) = -4^(-5/5) + 1/2 - (1/2)cos(t^2).

Step-by-step explanation:

To solve the given initial value problem (IVP), we can separate the variables and integrate both sides. Let's start by dividing both sides of the equation by (2x^6) and multiplying by dt to isolate dx. This gives us:

dx/(2x^6) = -tsin(t^2)dt

Next, we integrate both sides with respect to their respective variables:

∫dx/(2x^6) = ∫-tsin(t^2)dt

Integrating the left side gives us: x^-5/5 = -1/2cos(t^2) + C

Applying the initial condition x(0) = -4, we can find the value of the constant C. Substituting x = -4 and t = 0 into the equation gives us:

(-4)^-5/5 = -1/2cos(0) + C

Simplifying, we find that C = -4^(-5/5) + 1/2.

Therefore, the explicit solution to the IVP is:

x(t) = -4^(-5/5) + 1/2 - (1/2)cos(t^2)

User Suraj Kumar Maurya
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