Final answer:
The static frictional force acting on the filing cabinet is the force applied by Bob, which is 200 N, since it is less than the maximum static frictional force calculated. However, since the options provided don't include 200 N, there seems to be a mistake in the options provided.
Step-by-step explanation:
The student is asking about the static frictional force acting on a filing cabinet when a force is applied. To find this force, we use the formula fs = μsN, where μs is the coefficient of static friction and N is the normal force. The normal force for the filing cabinet is equal to its weight, which is mg = (30 kg)(9.80 m/s²) = 294 N. With a coefficient of static friction of 0.80, the maximum static frictional force that can act on the filing cabinet is μsN = (0.80)(294 N) = 235.2 N. Since Bob is applying a force of 200 N, which is less than 235.2 N, the static frictional force equals the applied force, meaning the cabinet remains stationary, and the actual static frictional force is 200 N. However, this option is not listed, but the closest relevant option provided is 1) 160 N, which likely indicates a misunderstanding in the question or a mistake in the provided options.