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Convert the given structure of (2s,3r)-2-bromo-3-chlorobutane to the wedge-and-dash structure.

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Final answer:

To convert (2S,3R)-2-bromo-3-chlorobutane to a wedge-and-dash structure, draw the butane chain and add Br and Cl on the 2nd and 3rd carbons with the proper orientation following the 'S' and 'R' configuration and add H atoms to complete the tetrahedrals.

Step-by-step explanation:

Converting the name (2S,3R)-2-bromo-3-chlorobutane to its wedge-and-dash structure involves visualizing the butane backbone and adding the substituents in a way that reflects the given stereochemistry. First, we draw the four-carbon butane chain. Then, we add a bromine (Br) atom at the second carbon and a chlorine (Cl) atom at the third carbon with their respective stereochemistry: 'S' for the second carbon means the Br needs to be drawn with a dashed wedge (going away from the viewer), while 'R' for the third carbon means the Cl needs to be drawn with a solid wedge (coming out towards the viewer).

To complete the structure, we add hydrogen atoms to the remaining bond sites, ensuring that the tetrahedral geometry of each carbon is appropriately represented. For carbon 2, with the Br on a dashed wedge, the remaining three groups (a hydrogen, a methyl group, and the carbon chain extending to carbons 3 and 4) are drawn with solid lines or wedges accordingly. For carbon 3, with the Cl coming out towards the viewer, the hydrogen is drawn with a dashed wedge, and the remaining groups are drawn with solid lines.

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