Final answer:
The decibel values of thermal noise power and thermal noise power density can be determined using the equations n = kTB and no = kB, where k is the Boltzmann constant, T is the temperature in Kelvin, and B is the bandwidth in Hz. Given the values T = 300 Kelvin and B = 24MHz, the calculated values for n and no are approximately 9.94 x 10^-14 J and 4.89 x 10^-21 J/Hz respectively.
Step-by-step explanation:
The decibel values of thermal noise power (n) and thermal noise power density (no) can be determined using the equations:
n = kTB and no = kB
Where:
k = Boltzmann constant (1.38 x 10^-23 J/K)
T = temperature in Kelvin
B = bandwidth in Hz
Given that the temperature (T) is 300 Kelvin and the bandwidth (B) is 24MHz (24 x 10^6 Hz), we can calculate the values as follows:
n = (1.38 x 10^-23 J/K) * (300 K) * (24 x 10^6 Hz)
no = (1.38 x 10^-23 J/K) * (300 K)
By performing the calculations, we find:
n &#approx; 9.94 x 10^-14 J
no &#approx; 4.89 x 10^-21 J/Hz