Final answer:
The fundamental frequency of a resonating tube filled with helium instead of air would increase, given the speed of sound in helium is greater than in air.
Step-by-step explanation:
The subject of the question is Physics, and it appears to be aimed at a High School level student. The student is asking about the change in the fundamental frequency of a resonating tube, such as the human vocal tract when filled with helium instead of air, while maintaining the same temperature.
In the context of acoustics and resonance, the speed of sound in a gas affects the frequency of the sound produced. Since the speed of sound in helium is greater than in air, due to its lower density, the fundamental frequency would increase if air in the resonating tube is replaced with helium. The formula for the fundamental frequency of a tube closed at one end is f = v / (4L), where f is the frequency, v is the speed of sound in the medium, and L is the length of the tube.
Given that the temperature remains constant at 37.0°C, we would use the speed of sound in helium at that temperature to calculate the new fundamental frequency.