Final answer:
The velocity of the confetti just before it reaches the ground can be determined using kinematics and the equation v = 9.8t, where v is the velocity and t is the time taken to reach the ground.
Step-by-step explanation:
The velocity of the confetti just before it reaches the ground can be determined using kinematics. Since the initial velocity of the confetti is given as 0 (vo = 0) and it is in free fall, we can use the equation v = gt, where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time it takes to reach the ground.
Let's assume the time taken to reach the ground is t. So, the velocity just before it hits the ground will be v = 9.8t m/s.
To find the time, we can use the equation h = (1/2)gt², where h is the height from which the confetti is dropped (the height of the room). Rearranging the equation, we get t = sqrt(2h/g).
Substituting the values, we can find the velocity just before it hits the ground.