Question

What is the magnitude of the magnetic force on a charged particle (q = 5.0 μc) moving with a speed of 80 km/s in the positive x direction at a point where bx = 5.0 t, by = -4.0 t, and bz = 3.0 t?

Answer 1

The magnitude of the magnetic force on the charged particle is 1.01 N.

Step-by-step explanation:

The magnetic force on a charged particle can be calculated using the equation F = qvBsinθ, where F is the magnitude of the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.

Given the values q = 5.0 μC = 5.0 × 10-6 C, v = 80 km/s = 80 × 103 m/s, and B = (5.0, -4.0, 3.0) T, we can calculate the magnitude of the force:

F = (5.0 × 10-6 C)(80 × 103 m/s)(√(5.02 + (-4.0)2 + 3.02))

Solving this equation gives F = 1.01 N.