9.2k views
5 votes
Determine whether the series [infinity] n - 1 3n - 1 n = 1 is convergent or divergent.

User Omer Maki
by
9.2k points

1 Answer

1 vote

Final answer:

To determine the convergence or divergence of the series with general term (n - 1)/3^(n - 1), one can apply the Ratio Test or the Comparison Test. However, due to possible typos in the original question, an exact answer is not provided.

Step-by-step explanation:

The student has asked to determine whether the series given by the general term n - 1/3n - 1 from n = 1 to infinity is convergent or divergent. To assess the convergence of the series, we must analyze its terms. First, simplifying the term of the series, we have (n - 1)/3^(n - 1), which we can compare to a known convergent series such as 1/3^n. By applying the Ratio Test or the Comparison Test, one can determine the behavior of the series. If the test indicates that the series terms become sufficiently small as n increases, the series is convergent; otherwise, it is divergent. However, without the clear context or correct notation, providing an exact answer is challenging. Nonetheless, using the mentioned tests provides a path forward in evaluating the series.

User SomeStudent
by
8.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories