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What is the probability that a student will neither do homework regularly nor will pass the course?

2 Answers

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Final answer:

To find the probability that a student will neither do homework regularly nor pass the course, use the complement rule by calculating (1-p) * (1-q).

Step-by-step explanation:

To find the probability that a student will neither do homework regularly nor pass the course, we can use the complement rule. Let's assume that the probability of doing homework regularly is p, and the probability of passing the course is q. Therefore, the probability of not doing homework regularly is 1-p, and the probability of not passing the course is 1-q.

The probability that a student will neither do homework regularly nor pass the course can be calculated as (1-p) * (1-q).

For example, if p = 0.7 (70%) and q = 0.8 (80%), the probability of not doing homework regularly and not passing the course would be (1-0.7) * (1-0.8) = 0.3 * 0.2 = 0.06, which is 6%.

User FeRtoll
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2 votes

Final answer:

To find the probability that a student will neither do homework regularly nor pass the course, multiply the probabilities of doing homework regularly and passing the course, then subtract the result from 1.

Step-by-step explanation:

To find the probability that a student will neither do homework regularly nor pass the course, we need to find the complement of the event that a student will do homework regularly and pass the course.

Let's assume that the probability of a student doing homework regularly is 0.70 and the probability of a student passing the course is 0.75. To find the probability of both events happening, we multiply the probabilities: 0.70 * 0.75 = 0.525.

Since we want the complement of this event, we subtract the result from 1: 1 - 0.525 = 0.475. Therefore, the probability that a student will neither do homework regularly nor pass the course is 0.475 or 47.5%.

User Khoekman
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