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36) In a room that measure 15-feet X 25-feet (4.5 meters X 7.6 meters) wit The entire floor wet, minimal wicking up the walls less than two feet (60 cm) and no offsets; initially, how many air movers should be added? A. 1-3 B. 4-6 C. 7-9 b>»«l»l«f»f»f»f D. 10-12​

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The 1 to 3 air mover should be added.

To determine the number of air movers needed to dry the entire floor with minimal whipping up the walls, we need to consider the square footage of the room.

The formula for calculating the square footage of a rectangular room is length multiplied by width.

Given that the room measures 15 feet by 25 feet:


\[ \text{Square footage} = \text{Length} * \text{Width} \]\[ \text{Square footage} = 15 \, \text{feet} * 25 \, \text{feet} \]\[ \text{Square footage} = 375 \, \text{square feet} \]

The industry standard for air movers is typically around 150-200 square feet of coverage per unit. Let's use a conservative estimate of 150 square feet.


\[ \text{Number of air movers needed} = \frac{\text{Total square footage}}{\text{Coverage per air mover}} \]\[ \text{Number of air movers needed} = \frac{375 \, \text{sq ft}}{150 \, \text{sq ft per air mover}} \]\[ \text{Number of air movers needed} = 2.5 \]

Since you can't have a fraction of an air mover, you would round up to the nearest whole number. Therefore, you would need at least 3 air movers to effectively dry the entire floor with minimal whipping up the walls.

So, the correct answer is 1-3.

Complete question:

In a room that measures 15 feet by 25 feet what the entire floor wet, minimal whipping up the walls or less than 2 feet of the walls and no offsets; initially how many air mover should be added?

1-3

4-6

7-9

10-12

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