Final answer:
To prepare 500.0 mL of a 0.30 M sulfuric acid solution, 25.0 mL of 6.0 M sulfuric acid is required, calculated using the dilution equation M1V1 = M2V2 and converting volumes to liters for unit consistency.
Step-by-step explanation:
Calculating the Volume of Concentrated Sulfuric Acid Needed for Dilution.
To find out the volume of 6.0 M sulfuric acid required to prepare 500.0 mL of a 0.30 M solution, we can use the dilution equation M1V1 = M2V2, where M1 represents the initial concentration, V1 represents the volume of the concentrated solution, M2 represents the final concentration, and V2 represents the final volume of the diluted solution.
First, we need to convert the final volume V2 from milliliters to liters because molarity is typically expressed in terms of liters. V2 = 500.0 mL = 0.500 L.
Using the provided information:
- M1 = 6.0 M (initial concentration)
- V1 = ? (volume of the concentrated solution needed)
- M2 = 0.30 M (final concentration)
- V2 = 0.500 L (final volume)
Now we can insert the values into the equation:
(6.0 M) × V1 = (0.30 M) × (0.500 L)
To solve for V1:
V1 = (0.30 M × 0.500 L) / 6.0 M
V1 = 0.025 L
Therefore, to prepare 500.0 mL of a 0.30 M sulfuric acid solution, 25.0 mL of 6.0 M sulfuric acid is required.