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What is the final velocity of the alpha particle, (vf)α?

User Ramie
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Final answer:

The final velocity of the alpha particle after moving through a potential difference of -3.45×10−3 V is approximately 1.77 × 10³ m/s. This was calculated by using the conservation of energy principle and considering the work done by the electric field on the alpha particle.

Step-by-step explanation:

To calculate the final velocity (vf) of the alpha particle after it has moved through a potential difference, we use the conservation of energy principle. The work done on the alpha particle by the electric field as it moves through a potential difference equals the change in the particle's kinetic energy.

Initial kinetic energy (Ki) + Work done by electric field (W) = Final kinetic energy (Kf).

Because the alpha particle is initially at rest, its initial kinetic energy is 0, so W = Kf.

The work done by the electric field is given by W = qα * V, where qα is the charge of the alpha particle and V is the potential difference. Here, qα = 3.20×10−19 C and V = −3.45×10−3 V. Plugging in the values, we get W = (3.20×10−19 C)(−3.45×10−3 V) = −10.44×10−19 J.

Since W = Kf, and the kinetic energy (Kf) can also be expressed as (1/2)mα*vβ, we can solve for the final velocity (vfα) as follows:

Kf = ½ mα(vfα)²

−10.44×10−19 J = ½ (6.68×10−27 kg)(vfα)²

(vfα)² = (2×−10.44×10−19 J) / (6.68×10−27 kg)

(vfα)² = −3.125×10−6 m²/s²

(vfα) = −sqrt(−3.125×10−6 m²/s²)

Since velocity can't be negative, we take the positive root:

(vfα) = sqrt(3.125×10−6) m/s ≈ 1.77 × 10³ m/s

The final velocity of the alpha particle is approximately 1.77 × 10³ m/s.

Complete Question:
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Conservation of energy in charge interactions. An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of −3.45×10−3 V . The charge and the mass of an alpha particle are qα = 3.20×10−19 C and mα = 6.68×10−27 kg , respectively.

What is the final velocity of the alpha particle, (vf)α?

Express your answer in meters per second using three significant figures.

User Chris Rutherfurd
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