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Find the directional derivative of the function f(x, y) = 7eˣ sin(y) at the point (0, π/3) in the direction of the vector v = (-5, 12).

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Final answer:

The directional derivative of the function f(x, y) = 7eˣ sin(y) at the point (0, π/3) in the direction of the vector v = (-5, 12) is 0.282.

Step-by-step explanation:

The directional derivative of a function represents the rate at which the function changes along a given direction. To find the directional derivative of the function f(x, y) = 7eˣ sin(y) at the point (0, π/3) in the direction of the vector v = (-5, 12), we can use the formula:

directional derivative = ∇f · u = ∂f/∂x * u₁ + ∂f/∂y * u₂

where ∇f is the gradient of f and u is the unit vector in the direction of v.

To calculate the gradient of f, we need to find ∂f/∂x and ∂f/∂y:

∂f/∂x = 7eˣ sin(y)

∂f/∂y = 7eˣ cos(y)

Next, we normalize the vector v to find the unit vector u:

u = v/|v| = (-5/13, 12/13)

Finally, we substitute the values into the formula to find the directional derivative:

directional derivative = ∂f/∂x * u₁ + ∂f/∂y * u₂ = (7e⁰ sin(π/3)) * (-5/13) + (7e⁰ cos(π/3)) * (12/13) = 0.282

User RyanY
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