Question

how many array accesses are there in the code snippet below?int count = 0;for (int i = 0; i < n; i ) { for (int j = i 1; j < n; j ) { if (a[i] a[j] == 0) { count ; } }}

Answer 1

In the code snippet provided, there are n² array accesses.

Step-by-step explanation:

The code contains two nested loops, each iterating from 0 to ( n - 1 ). The outer loop runs n times, and for each iteration of the outer loop, the inner loop also runs n times. Within the inner loop, there is an array access with the statements `a[i]` and `a[j]` where `i` and `j` represent the loop variables.

As a result, for every combination of `i` and `j`, there is an array access. This leads to n iterations of the outer loop, and for each iteration of the outer loop, the inner loop performs n array accesses, resulting in a total of ( n × n = n²) array accesses throughout the execution of the code.

Here is complete question;

"How many array accesses are there in the code snippet below?int count = 0;for (int i = 0; i < n; i ) { for (int j = i 1; j < n; j ) { if (a[i] a[j] == 0) { count ; } }}"