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1 =

2 + 3 − 7
2 = − 4
Use the range of − ≤ ≤
Note: When = −6, 1 = (−6)
2 + 3 (−6) − 7 = 36 − 18 − 7 = 11
When = −6, 2 = −6 − 4 = −10

1 Answer

7 votes

Inconsistent solutions: x = -6 implies y = -1/3, contradictory to y = -4 in the given range.

In the given system of equations, the second equation y = -4 is straightforward, indicating that y always equals -4. However, the first equation x = 2 + 3y - 7 includes x expressed in terms of y.

Initially, x is expressed as a function of y, where x = 2 + 3y - 7. Simplifying this gives x = 3y - 5.

When x = -6 (as per the specified range), substituting it into the derived equation gives:

-6 = 3y - 5

Solving for y yields 3y = -1 and y = -1/3. However, this contradicts the range constraint where y should be -4.

This discrepancy arises due to a misinterpretation of the original equations. The given range, x = -6, is incompatible with the second equation y = -4, as it results in a contradictory value for y. This inconsistency suggests that the system of equations might not hold for the provided range of x.

The initial equations seem to be at odds when values are substituted, leading to a contradiction between the range specified and the solutions derived from the equations. Consequently, it's crucial to re-evaluate the equations or adjust the constraints to ensure coherence within the system.

Question:

Given the system of equations:

1. x = 2 + 3y - 7

2. y = -4

Utilizing the range
\(-6 \leq x \leq -6, when x = -6, the value of y is determined as y = -6 - 4 = -10. However, substituting these values back into equation 1 doesn't yield the expected result. Explain the inconsistency.

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