Final answer:
The complete ionic equation for the reaction between hydroiodic acid (HI) and a generic metal hydroxide (RBOH) is represented by combining the ions HI(aq) and RBOH(aq) to produce water (H2O) and the resultant salt composed of RB+ and I-. The net ionic equation is simplified to H+(aq) + OH-(aq) → H2O(l).
Step-by-step explanation:
Complete Ionic Equation for an Acid-Base Reaction
The question asks to enter the balanced complete ionic equation for the acid-base reaction between hydroiodic acid (HI) and a generic metal hydroxide (RBOH). The general format for an acid-base neutralization reaction is as follows:
- Write the formula of the acid and base in the reactants and the salt and water in the products.
- Balance the H+ in the acid with the OH− in the base.
- Balance the remaining elements and charges.
Since HI is a strong acid and RBOH is a strong base, they will both dissociate completely in solution, leading to their respective ions. The reaction will produce water (H2O) and the salt composed of the cation from RBOH and the anion from HI, which is RB+ and I−, respectively.
The balanced ionic equation is:
H+(aq) + I−(aq) + RB+(aq) + OH−(aq) → RB+(aq) + I−(aq) + H2O(l)
The spectator ions, RB+ and I−, can be canceled out since they appear on both sides of the equation, leaving us with:
H+(aq) + OH−(aq) → H2O(l)
This is the net ionic equation for the reaction between hydroiodic acid and a generic metal hydroxide, illustrating the formation of water as a result of the acid-base neutralization.