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what concentration of ClO3- results when 935mL of .319 M AgClO3 is mixed with 763 mL of .457M Mn(ClO3)2?

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Final answer:

To find the concentration of ClO3- in the mixture, calculate the moles of each component and use the volumes to determine the concentration. The concentration of ClO3- in the mixture is 0.381 M.

Step-by-step explanation:

To find the concentration of ClO3- in the mixture, we need to calculate the moles of each component and then use the volumes to determine the concentration.

First, calculate the moles of AgClO3 using the equation:

moles = volume (L) x concentration (M)

moles of AgClO3 = 935 mL x 0.319 M

= 298.165 mol ClO3-

Then, calculate the moles of Mn(ClO3)2 using the same equation:

moles of Mn(ClO3)2 = 763 mL x 0.457 M

= 348.991 mol ClO3-

Next, add the moles of ClO3- from both components:

total moles of ClO3- = 298.165 mol + 348.991 mol

= 647.156 mol ClO3-

Finally, calculate the concentration of ClO3- in the mixture using the total moles and the total volume:

concentration = total moles / total volume

concentration = 647.156 mol / (935 mL + 763 mL)

=0.381 M ClO3-

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