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What is the half-life rate constant (s-1) of a first order process that has a half-life of 493 s?

User Idkt
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Final answer:

The half-life rate constant (k) for a first-order process with a half-life of 493 seconds is calculated using the equation k = 0.693 / t1/2, resulting in a rate constant of 0.001406 s-1.

Step-by-step explanation:

To find the half-life rate constant (k) for a first order process given the half-life (t1/2) of 493 seconds, we can use the following equation derived from the first-order kinetics equation:

k = 0.693 / t1/2

Substituting the given half-life into the equation gives us:

k = 0.693 / 493 s = 0.001406 s-1.

This is the rate constant for the reaction with a half-life of 493 seconds. It represents how quickly the concentration of a reactant decreases to half its initial concentration in a first-order reaction process.

User CelinHC
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