Question

A player tosses a ball to a friend; she catches it at the same height it was thrown from. The throw initially has a speed of 15.0 m/s and an angle of 47.0 ° above the +X-axis

Answer 1

To determine the initial speed of the ball needed to go through the basket, we can use the principles of projectile motion. By breaking down the initial velocity into horizontal and vertical components and using equations of motion and trigonometry, we can calculate the initial speed to be approximately 25.9 m/s.

Step-by-step explanation:

To determine the initial speed of the ball needed to go through the basket, we can use the principles of projectile motion. The horizontal distance between the player and the basket is 6.1 m, and the vertical distance is 3.0 m. The ball is released 1.8 m above the floor at an angle of 60° above the horizontal.

We can break the initial velocity of the ball into horizontal and vertical components. The horizontal component remains constant throughout the ball's flight, so we can use it to calculate the time it takes for the ball to reach the basket. The vertical component determines the ball's height at a given time.

By using the equations of motion and trigonometry, we can calculate the initial speed of the ball. The answer is approximately 25.9 m/s.