Question

you have a mixture that is composed of 27% of the (+) enantiomer and 73% the (-) enantiomer. what is the ee of the mixture? (give you answer in the form of a percent.)

Answer 1

The enantiomeric excess (ee) of a mixture is a measure of the excess of one enantiomer over the other. In this case, the mixture is composed of 27% of the (+) enantiomer and 73% of the (-) enantiomer. To calculate the ee of the mixture, subtract the percentage of the (-) enantiomer from the percentage of the (+) enantiomer.

Step-by-step explanation:

The enantiomeric excess (ee) of a mixture is a measure of the excess of one enantiomer over the other. To calculate the ee of the mixture, you need to know the percentages of each enantiomer present. In this case, the mixture is composed of 27% of the (+) enantiomer and 73% of the (-) enantiomer. To calculate the ee, you subtract the percentage of the (-) enantiomer from the percentage of the (+) enantiomer:

ee = % (+) enantiomer - % (-) enantiomer

ee = 27% - 73%

ee = -46%

Therefore, the enantiomeric excess of the mixture is -46%.