Question

You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each of the following reactions:

a. The yellow precipitate formed in the reaction between KI and Pb(NO₃)₂ is .
b. The white precipitate formed in the reaction between BaCl₂ and H₂SO₄ is .
c. The brown precipitate formed in the reaction between NaOH and FeCl₃ is .
d. The blue precipitate formed in the reaction between CuSO₄ and NaOH is .

Answer 1

In several double-replacement reactions, the resulting precipitates include lead iodide, barium sulfate, iron(III) hydroxide, and copper(II) hydroxide, which are yellow, white, brown, and blue precipitates, respectively.

Step-by-step explanation:

In a lab exercise observing the formation of precipitates via double-replacement reactions, the precipitates formed can be identified as follows:

• a. The yellow precipitate formed in the reaction between KI (potassium iodide) and Pb(NO₃)₂ (lead nitrate) is PbI₂ (lead iodide).
• b. The white precipitate formed in the reaction between BaCl₂ (barium chloride) and H₂SO₄ (sulfuric acid) is BaSO₄ (barium sulfate).
• c. The brown precipitate formed in the reaction between NaOH (sodium hydroxide) and FeCl₃ (iron(III) chloride) is Fe(OH)₃ (iron(III) hydroxide).
• d. The blue precipitate formed in the reaction between CuSO₄ (copper(II) sulfate) and NaOH is Cu(OH)₂ (copper(II) hydroxide).