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A gas sample is heated from -20.0°C to 57.0°C and the volume is increased from 2.00 L to 4.50 L. If

User Roohan
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Final answer:

The student's question pertains to the changes in a gas sample's volume with respect to its temperature, based on high school chemistry principles involving Charles's Law, which correlates volume and temperature of a gas.

Step-by-step explanation:

The question asked concerns the physical behavior of a gas sample when it undergoes changes in temperature and volume. This is a topic typically covered in high school chemistry classes, particularly when discussing the gas laws - equations that relate the pressure, volume, temperature, and amount of gas. The question doesn't provide pressure or amount, so it may be addressing Charles's Law, which states that the volume of a gas is directly proportional to its temperature in kelvins, as long as the pressure and amount of gas remain constant. From the question, the gas is initially at -20.0°C (253.15 K) and 2.00 L. It is heated to 57.0°C (330.15 K), and its volume increases to 4.50 L. To determine how these changes are related, one could use Charles's Law (V1/T1 = V2/T2), adjusting temperatures to the Kelvin scale, where T = °C + 273.15, and solving for the unknown variable.

User MMiroslav
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