Final answer:
The electric flux through a surface with area 6.66×10^-4 m2 at an angle of 60° to an electric field is calculated with Φ = E * A * cos(θ).
Step-by-step explanation:
The question is asking to calculate the electric flux through a surface area when the electric field is at an angle to the surface. The electric flux Φ through a surface is given by the formula Φ = E * A * cos(θ), where E is the magnitude of the electric field, A is the area of the surface, and θ is the angle between the field and the perpendicular to the surface. In this case, the electric field makes an angle of 60° with the surface, which is the complementary angle to the normal. Since the cosine of 60° is 0.5, the electric flux can be found by multiplying half of the surface area by the electric field strength.
To solve this, first identify the given values: the surface area A = 6.66×10-4 m2, and the angle θ = 60°. The electric field was not specified in the question, but we'll assume there is an electric field E given. The cosine of 60° is 0.5, hence, the electric flux Φ = E * A * cos(60°) = E * 6.66×10-4 m2 * 0.5. If E were provided, we would insert its value here to calculate Φ.