Question

Rank the magnitude of the electric field in these five cases.

1) Case 1 has the highest magnitude of electric field.
2) Case 2 has the highest magnitude of electric field.
3) Case 3 has the highest magnitude of electric field.
4) Case 4 has the highest magnitude of electric field.
5) Case 5 has the highest magnitude of electric field.

Answer 1

The ranking of the magnitude of the electric field in these five cases is as follows:

1. Case 4 has the highest magnitude of electric field.

2. Case 5 has the second-highest magnitude of electric field.

3. Case 2 has the third-highest magnitude of electric field.

4. Case 1 has the fourth-highest magnitude of electric field.

5. Case 3 has the lowest magnitude of electric field.

Step-by-step explanation:

The magnitude of the electric field
`(\(E\))` is determined by the formula
`\(E = (k \cdot q)/(r^2)\),` where
`\(k\)` is Coulomb's constant,
`\(q\)` is the charge, and
`\(r\)` is the distance from the charge. In the context of the question, the ranking can be deduced based on the given cases.

The key factor influencing the magnitude of the electric field is the product of the charge and the inverse of the square of the distance. Higher charges and shorter distances lead to higher electric field magnitudes. Therefore, by analyzing the given cases, it can be inferred that Case 4 has the highest charge and the shortest distance, resulting in the highest electric field magnitude. Conversely, Case 3 has the lowest charge and the longest distance, leading to the lowest electric field magnitude.

Understanding the relationship between the variables in the electric field formula is crucial for ranking the magnitudes appropriately. In this case, the provided ranking corresponds to the variations in charge and distance for each case, reflecting their impact on the electric field strength.