Final answer:
The magnitude of the electric field just inside the cell wall is approximately 8.89 x 10^6 V/m, calculated by dividing the voltage (80.0 mV) by the thickness of the membrane (9.00 nm).
Step-by-step explanation:
To calculate the magnitude of the electric field just inside the cell wall, we use the relationship between electric field (E), voltage (V), and distance (d). The electric field is given by the equation E = V/d, where V is the voltage across the membrane and d is the thickness of the membrane. Given the voltage across the membrane is 80.0 mV or 0.080 V, and the thickness of the membrane is 9.00 nm or 9.00 x 10-9 meters, the electric field strength E can be calculated as follows:
E = 0.080 V / 9.00 x 10-9 m
Calculating this, we find:
E ≈ 8.89 x 106 V/m
This result indicates that the electric field strength just inside the cell wall is approximately 8.89 million volts per meter, which is indeed a surprisingly large value.