Answer:
11:60
Explanation:
In ΔHIJ, given the measure of ∠J=90°, JI = 48, IH = 73, and HJ = 55. We are to find tan<H
Using SOH CAH TOA
tan theta = opposite/adjacent
JI is the opposite (facing m<H)
HJ will be adjacent
tan m<H = JI/HJ
tan m<H = 48/55
tan m<H = 0.87 (to the nearest hundredth)
In ΔJKL, the measure of ∠L=90°, JL = 60, KJ = 61, and LK = 11. What ratio represents the tangent of ∠J?
Using SOH CAH TOA
tan theta = opposite/adjacent
LK is the opposite (facing m<J)
JL will be adjacent
tan m<J = LK/JL
tan m<H = 11/60
Hence the ratio that represents the tangent of ∠J is 11:60