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Find the exact area of the surface obtained by rotating the curve y = cos(18x) about the x-axis, where 0 ≤ x ≤ 4?

User Xanadont
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Final answer:

To find the exact area of the surface obtained by rotating the curve y = cos(18x) about the x-axis, we need to use the formula for the surface area of a solid of revolution. The formula is given by: A = 2π ∫[a,b] f(x) sqrt(1 + (f'(x))^2) dx. In this case, f(x) = cos(18x). We can plug in the values for a and b, which are 0 and 4 respectively, to find the exact area using integration.

Step-by-step explanation:

Find the exact area of the surface obtained by rotating the curve y = cos(18x) about the x-axis, where 0 ≤ x ≤ 4?



To find the exact area of the surface obtained by rotating the curve y = cos(18x) about the x-axis, we need to use the formula for the surface area of a solid of revolution. The formula is given by:



A = 2π ∫[a,b] f(x) sqrt(1 + (f'(x))^2) dx



In this case, f(x) = cos(18x). We can plug in the values for a and b, which are 0 and 4 respectively, to find the exact area using integration.

User Change
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