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Find the distance between the skew lines with parametric equations x = 2t, y = 36t, z = 2t, and x = 22s, y = 414s, z = -35s?

User Asqan
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Final answer:

The distance between the given skew lines is zero since both lines intersect at the origin after solving for points by setting t and s to zero. The explanatory steps provided elucidate how to find the distance in a general case where the lines do not intersect.

Step-by-step explanation:

To find the distance between skew lines, we need to find a vector that is perpendicular to both lines and use it to create a vector between points on each line. The parametric equations given are:

  • Line 1: x = 2t, y = 36t, z = 2t
  • Line 2: x = 22s, y = 414s, z = -35s

The direction vectors of the lines can be found from the coefficients of t and s respectively:

  • Direction of Line 1: ɣ1 = (2, 36, 2)
  • Direction of Line 2: ɣ2 = (22, 414, -35)

The vector perpendicular to both is the cross product of the direction vectors:

Perpendicular Vector = ɣ1 x ɣ2

Let's find a point on each line by letting t = 0 for Line 1 and s = 0 for Line 2, we obtain:

  • Point on Line 1: P1 = (0, 0, 0)
  • Point on Line 2: P2 = (0, 0, 0)

However, because both points are at the origin, the distance is obviously zero. But in a more general case where the points are not the same, we would use the following steps:

  • Construct a vector ɣ3 = P2 - P1
  • Find the distance d using the dot product between ɣ3 and the Perpendicular Vector
  • Finally, divide by the magnitude of the Perpendicular Vector to get the shortest distance d

User Ed Peguillan III
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