Final answer:
The distance traveled by an oscillator in 5.5 periods is equal to 5.5 times its amplitude.
Step-by-step explanation:
In simple harmonic motion, the distance traveled by an oscillator in one time period is equal to the amplitude of the motion. Therefore, in this case, the distance traveled by the oscillator in 5.5 periods would be equal to 5.5 times the amplitude, which is represented by the variable a.
Distance traveled by the oscillator = 5.5a
For example, if the amplitude of the oscillator is 2 meters, then the distance traveled in 5.5 periods would be 5.5 x 2 = 11 meters.