Question

If a wire carries a current of 2.0 A and is bent into a circular loop of radius 5.0 cm, what is the magnitude of the magnetic field at the center of the loop?

1) 0.4 T
2) 0.8 T
3) 1.2 T
4) 1.6 T

Answer 1

The magnitude of the magnetic field at the center of the circular loop is approximately 12.56 A.

Step-by-step explanation:

To find the magnitude of the magnetic field at the center of the circular loop, you can use Ampere's law. Ampere's law states that the magnetic field at a point on a closed loop is the product of the current passing through the loop and the circumference of the loop divided by 2 times the radius. In this case, the current is 2.0 A and the radius of the loop is 5.0 cm. To find the circumference, you can use the formula 2 * pi * radius. Plugging in the values, you get:

Magnetic field = (2.0 A * 2 * pi * 5.0 cm) / (2 * 5.0 cm)

Simplifying the equation, you get:

Magnetic field = 2 * pi * 2.0 A = 4.0 pi A

Approximating pi as 3.14, the magnetic field is approximately 12.56 A.

Therefore, the magnitude of the magnetic field at the center of the loop is approximately 12.56 A.