Question

In a slap shot, a hockey player accelerates the puck from a velocity of 9.00 m/s to 30.0 m/s in the same direction. If this takes 3.33 × 10-2 s, calculate the distance over which the puck accelerates?

Answer 1

To calculate the distance over which the puck accelerates in a slap shot, use the formula d = (v_f^2 - v_i^2) / (2a), where d is the distance, v_f is the final velocity, v_i is the initial velocity, and a is the acceleration. By substituting the given values into the formula, the distance can be calculated.

Step-by-step explanation:

To calculate the distance over which the puck accelerates in a slap shot, we can use the formula:

d = (vf2 - vi2) / (2a)

where d is the distance, vf is the final velocity, vi is the initial velocity, and a is the acceleration.

Given that vi = 8.00 m/s, vf = 40.0 m/s, and the time taken is 3.33 × 10-2 s, we can calculate the acceleration using the formula:

a = (vf - vi) / t

Substituting the values into the formula, we get:

a = (40.0 - 8.00) / (3.33 × 10-2)

Finally, substituting the values of a, vf, and vi into the formula for distance, we can calculate the distance over which the puck accelerates.