Final answer:
The specific volume of R-134a at 20°C and 630 kPa is approximately 0.277 L/mol.
Step-by-step explanation:
The specific volume of a substance is defined as the volume occupied by one unit of mass of the substance. In order to calculate the specific volume of R-134a at 20°C and 630 kPa, we need to use the ideal gas equation.
The ideal gas equation is given by:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
To solve for the specific volume, we need to rearrange the ideal gas equation to isolate V:
V = (nRT) / P
Now we can substitute the given values into the equation:
V = (1 mol * 8.314 J/(mol·K) * (20°C + 273.15 K)) / 630 kPa
V ≈ 0.277 L/mol