Question

At room temperature, an oxygen molecule, with a mass of 5.31×10-26 kg, typically has a kinetic energy of about 6.21×10-21 J. What is the kinetic energy of the oxygen molecule at room temperature?

Answer 1

The kinetic energy of an oxygen molecule at room temperature can be calculated using the formula KE = (1/2)mv².

Step-by-step explanation:

The kinetic energy (KE) of a particle can be calculated using the formula KE = (1/2)mv², where m is the mass of the particle and v is its velocity. To find the kinetic energy of an oxygen molecule at room temperature, we can use the given mass of the oxygen molecule (5.31×10⁻²⁶ kg) and the average speed of an air molecule at room temperature (500 m/s).

So, the kinetic energy of the oxygen molecule can be calculated as:
KE = (1/2)mv²
= (1/2)(5.31×10⁻²⁶ kg)(500 m/s)²
= 6.6375×10⁻²¹ J

Therefore, the kinetic energy of the oxygen molecule at room temperature is approximately 6.6375×10⁻²¹ J.