Final answer:
The dissociation equation for strontium phosphate is Sr3(PO4)2 (s) → 3Sr2+ (aq) + 2PO43- (aq), and its solubility product (Ksp) is represented by the expression Ksp = [Sr2+]^3 [PO43-]^2.
Step-by-step explanation:
The dissociation equation for strontium phosphate (Sr3(PO4)2) involves the breakdown of the solid compound into its ions when it is dissolved in water. Strontium phosphate dissociates according to the following equation:
Sr3(PO4)2 (s) → 3Sr2+ (aq) + 2PO43- (aq)
Following stoichiometry, for each mole of Sr3(PO4)2 that dissolves, 3 moles of Sr2+ and 2 moles of PO43- ions are produced. Hence, the solubility product constant (Ksp) for strontium phosphate can be expressed as:
Ksp = [Sr2+]3 [PO43-]2
This equation is analogous in format to the other dissolution equations provided for calcium phosphate and lead(II) fluoride. It follows that the dissociation of strontium phosphate in water is a key concept in understanding the solubility product (Ksp).