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Two light bulbs have resistances of 400Ω and 800Ω.

Calculate the current flowing through each light bulb when connected separately to a 120V power source.

User AKA
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Final answer:

The current flowing through the light bulb with a resistance of 400Ω is 0.3A, and the current flowing through the light bulb with a resistance of 800Ω is 0.15A when each is connected separately to a 120V power source.

Step-by-step explanation:

To calculate the current flowing through each light bulb when connected separately to a 120V power source, you need to use Ohm's law, which states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. The formula is I = V/R.

For the bulb with a resistance of 400Ω:

Current (I) = Voltage (V) / Resistance (R) = 120V / 400Ω = 0.3A

For the bulb with a resistance of 800Ω:

Current (I) = Voltage (V) / Resistance (R) = 120V / 800Ω = 0.15A

User Chie
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